![]() Plus the syntax is simpler (so it may be more quickly understood by many readers/maintainers). With that way, it's clear your goal is to select lines that contain one thing but not another. If you want to display all lines that contain a sequence of four digits that is itself not part of any longer sequence of digits, one way is: grep -P '(?example: Which uses regular expression syntax to match lines that contain all words complete until complete on the same line. ⢠that contains a four-digit sequence but no longer sequence of digits (not even separately).įor example, (1) would display 1234a56789, but (2) wouldn't. If you are searching to match across multiple words on the same line, the grep command takes the form: grep âfrom.toâ .that contain a sequence of four digits that is itself not part of any longer sequence of digits, or.But the above command prints nothing and the reason I believe is it is not able to match anything. echo 'This is 02G05 a test string 2' sed -n '/\d+G\d+/p'. Different syntaxes for writing regular expressions have existed since the 1980s, one being the POSIX standard and another, widely used, being the Perl syntax. ![]() For that I tried the following regex with sed. The following commands do exactly the same: They print every line with a lowercase âtâ in it: (A1) lsblsb-t61-mint grep âtâ testgrep-tabs.txt (A2) lsblsb-t61-mint grep -e âtâ testgrep-tabs. Now from the above string I want to extract 02G05. There are two ways to interpret this question I'll address both cases. My example string is as follows: This is 02G05 a test string 2.
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